IPv6 PI allocation

[Mohacsi Janos]

On Fri, 18 May 2007, Roger J?rgensen wrote:

> On fre, mai 18, 2007 01:40, Colm MacCarthaigh wrote:
>> Address-conservation is a non-goal, it doesn't matter, there really is
>> plenty. There are 2^64 /64's. Even if we assigned only /32's to AS's,
>> another policy which would reduce the routing table size in sillicon,
>> there are still 2^21 of those publically assignable, probably enough to
>> see is through the entire lifetime of IPv6 (though it's not a bet I'd be
>> willing to take, overprovisioning by insane ammounts is a good idea).
>
> actual no, there isn't all that many addresses. In total there is 2^128
> addresses, then there is 2^64 that goes to the host-part.  Then we have
> the network part, let's use /32 since that is what most people have. All
> in all. That mean the total amount of network in IPv6 is 2^32 IF everyone
> get a /32 but that's not the case. Not are the entire address space usable
> either.
>
> We have 2^3 that goes away due to only 2000::/3 are usable for now, then
> we have the difference between /32 and a /29 are the biggest prefix
> assigned to anyone until today...
>
> That leave us with 32-3-(32-29) = 26... the highest amount of network
> available are something around 2^26. It's not _that_ many really.
>

Majority between /29 and /32. But I see
3x /28
3x /27
1x /24
2x /22
2x /21
3x /20
2x /19

However these prefix does not make your calculation worse. But there are 
plenty of /48 also.... I theur number will increase.
Regards,

Janos Mohacsi
Network Engineer, Research Associate, Head of Network Planning and Projects
NIIF/HUNGARNET, HUNGARY
Key 70EF9882: DEC2 C685 1ED4 C95A 145F  4300 6F64 7B00 70EF 9882